$CH_3-C\equiv CH \xrightarrow{O_3/Zn, H_2O_2} \text{Product}$ The product in the above reaction is
- A$CH_3COOH$
- B$HCOOH$
- C$\text{Both } (a) \text{ and } (b)$
- D$CH_3CHO + HCHO$
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